Today, I took a look at this simple-looking problem. It’s mainly Bit Manipulation, where you need to find the number of bits required to change one Integer to another.

In about 15 mins, I was able to make a few good solutions. Tell me which one you like better! It’s mainly a matter of taste. Being that Integers have 32 bits in Java, no matter which algorithm you use, the time complexity will be **O(1)** and there is obviously no need for extra space so space complexity will also be **O(1)**

## Find The Number of Bits Required to Change one Integer to Another

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/* * @Author: Ajk Palikuqi * * @Question: How To Find The Number of Bits Required to Change one Integer to Another. */ package iqLib.bitLib; public class BitsToConvertInts { public static int getNumberOfBitsToConvertInts(int src, int dest) { int temp = src; int count = 0; while (temp != 0) { if ((src & 1) == (temp & 1)) { count++; } temp = temp >> 1; } return count; } public static int getNumberOfBitsToConvertInts2(int src, int dest) { int temp = src ^ dest; int count = 0; while (temp != 0); { count += (temp ^ 1); } return count; } public static int getNumberOfBitsToConvertIntsGeeky(int src, int dest) { int temp = src ^ dest; // Hamming Weight algorithm temp = (temp & 0XAAAAAAAA) >> 1 + (temp & 0X55555555); temp = (temp & 0XCCCCCCCC) >> 2 + (temp & 0X33333333); temp = (temp & 0XF0F0F0F0) >> 4 + (temp & 0X0F0F0F0F); temp = (temp & 0XFF00FF00) >> 8 + (temp & 0X00FF00FF); temp = temp >> 16 + (temp & 0X0000FFFF); return temp; } public static int getNumberOfBitsToConvertIntsEasy(int src, int dest) { return Integer.bitCount(src ^ dest); } } |

If you are interested in another language you could check-out Bit swaps required to convert an Integer in C

Hope you guys enjoyed some quick coding… and I’ll see you guys next time ;D

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